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A 2 kΩ resistor and a 0.002 µF capacitor are in series across an ac source. Current in the circuit is 6.50 mA. The true power is

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Correct Answer: Option A
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1 Comment
Afifa
Afifa 3 years ago
Due to capacitance or inductance we get reactive power (Q).
The real power (S) depends on only resistance.
therefore,
S=VI=(I^2) R
By solving we get,
S= 84.5 mA