A 2 Ω RL is connected across a voltage source, VS, of 110 V. The source's internal resistance is 24 Ω. What is the output voltage across the load?
A. 8.5 V
B. 85 V
C. 0 V
D. 110 V
Answer: Option A
This Question Belongs to Electrical Engineering >> Circuit Theorems And Conversions
Voltage divider rule
(main voltage * resistance of the same branch)/sum of resistances
= (110 * 2)/(24 + 2) = 8.46.