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A 2 Ω RL is connected across a voltage source, VS, of 110 V. The source's internal resistance is 24 Ω. What is the output voltage across the load?

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Correct Answer: Option A
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1 Comment
Afifa A
Afifa A 3 years ago
Voltage divider rule
(main voltage * resistance of the same branch)/sum of resistances
= (110 * 2)/(24 + 2) = 8.46.