A 300 mm long conductor is carrying a current of 10 A and is situated at right angles to a magnetic field having a flux density of 0.8 T ; the force on the conductor will be
A. 240 N
B. 24 N
C. 2.4 N
D. 0.24 N
Answer: Option C
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Use F=BILsinθ.
Here
B=0.8 T,
I=10 A,
L=300 mm=0.3 m, and
𝜃=90⇒sinθ=1.
So,
F=0.8×10×0.3=2.4 N.
F=Bilsinthita
=0.8×10×0.3×1
=2.40N