A 3.3 kΩ resistor and a 120 mH coil are in parallel. Both components are across a 2 kHz, 12 V ac source. The total current in the circuit is
A. 8.74 mA
B. 874 mA
C. 874 µA
D. 8.74 µA
Answer: Option A
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Related Questions on RL Circuits
If the frequency is halved and the resistance is doubled, the impedance of a series RL circuit
A. Doubles
B. Halves
C. Remains constant
D. Cannot be determined without values
When the frequency is decreased, the impedance of a parallel RL circuit
A. Increases
B. Decreases
C. Remains constant
D. Is not a factor
Inductive reactance XL = 2πfL
XL = 6.28 × 2000 × 120
XL = 1.5072 kΩ
{
m{ = }} rac{{(1.50)(3.3)}}{{sqrt {{{(3.3)}^2} + {{(1.50)}^2}} }}
Z = 1.367 kΩ
The total current in the circuit I
I = V/Z = 12/1.367
I = 8.74 mA