A 680 Ω load resistor, RL, is connected across a constant current source of 1.2 A. The internal source resistance, RS, is 12 kΩ. The load current, RL, is

Solution (By Examveda Team)

The load current is determined by analyzing the circuit and applying Ohm's law and the voltage-divider principle.

Given:

Load resistance, R_L = 680 Ω

Internal source resistance, R_S = 12 kΩ = 12,000 Ω

Constant current source, I_S = 1.2 A

Step 1: Determine the total voltage of the circuit

The total voltage generated by the current source is:

V_total = I_S × R_S = 1.2 A × 12,000 Ω = 14,400 V

Step 2: Calculate the equivalent resistance

The load resistor and internal source resistance form a voltage divider. The voltage across R_L is calculated as:

V_L = V_total × (R_L / (R_L + R_S))

V_L = 14,400 × (680 / (680 + 12,000))

V_L = 14,400 × (680 / 12,680) = 774 V

Step 3: Find the load current

The load current is:

I_L = V_L / R_L = 774 / 680 = 1.14 A