A 680 Ω load resistor, RL, is connected across a constant current source of 1.2 A. The internal source resistance, RS, is 12 kΩ. The load current, RL, is
A. 0 A
B. 1.2 A
C. 114 mA
D. 1.14 A
Answer: Option D
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Current division rule
IL = (Is*Rs)/(Rs + Rl)