A 750 W electric iron is used for 8 hours per day. So the energy consumed in one day by iron is ?
A. 60 units
B. 0.6 units
C. 600 units
D. 6 units
Answer: Option D
Solution (By Examveda Team)
To calculate the energy consumed by the electric iron in one day, we can use the formula:Energy = Power × Time
Given: Power of the electric iron P = 750W Time the electric iron is used per day t = 8hours
First, we need to convert the time from hours to hours: t=8×1=8 hours
Now, we can calculate the energy consumed: Energy=750×8=6000 watt-hours
Since 1 kilowatt-hour (kWh) is equal to 1 unit of electricity, we need to convert the energy from watt-hours to units: Energy in units = $$\frac{6000}{1000}$$ = 6 units
Therefore, the energy consumed in one day by the electric iron is 6 units.
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