a + b + c = 0, then the value of $$\frac{{{a^2} + {b^2} + {c^2}}}{{ab + bc + ca}}$$ is?
A. 2
B. -2
C. 0
D. 4
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {\text{If }}a + b + c = 0 \cr & {\text{Put }}a = 1,{\text{ }}b = 1{\text{ and }}c = - 2 \cr & \therefore \frac{{{a^2} + {b^2} + {c^2}}}{{ab + bc + ca}} \cr & = \frac{{1 + 1 + 4}}{{1 - 2 - 2}} \cr & = \frac{6}{{ - 3}} \cr & = - 2 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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