A box contains 5 green, 4 yellow and 3 white marbles. Three marbles are drawn at random. What is the probability that all they are not of the same colour?
A. 3/44
B. 3/55
C. 52/55
D. 41/44
Solution (By Examveda Team)
Let balls are GGGGG, YYYY and WWW.
So, we could solve this question in 2 different ways:
The question can be solve by consedring the two senarios:
1) We can calculate the things that we want in above case senarios is not the same colour.
2. The things we don't want. In this senario we can calculate the answer (1 - we don't want ).
So, the scenarios we don't want are:
Probability of Getting a Green ball from the box = (5/12) * (4/11) * (3/10) = 60/1320
Probability of Getting Yellow ball = (4/12) * (3/11) * (2/10) = 24/1320
Probability of Getting White Ball = (3/12) * (2/11) * (1/10) = 6 /1320
So, Probability of getting Green or Yellow or White ball = (60/1320) + (24/1320) + (6/1320) = 9/132 = 3/44.
**"Not of the same colour" means that "not all 3 can be the same colour". So, you need to take into account the scenarios in which you have 2 of 1 colour and 1 of a second colour.
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Comments (7)
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Can you please explain @Leelanand Kumar?
3/44
Post Your Answer...
A is the answer
3/44
First find out the probablity that they all are in the same colour and then remaining we will find by 1-same color probablity..
here they are in the same colur means (5/12)*(4/11)*(3/10)+(4/12)*(3/11)*(2/10)+(3/12)*(2/11)*(1/10)=3/44 so we got here probablity of having same colour now to find out the remaining that means of having probablity of diffrent colur so just do 1-(3/44) then we will get the answer as 41/44..
Akash Thakur MIT Pune
You are wrong DEAR TEAMEXAMVEDA 1-3/44= 41/44... this is the answer.....
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