A capacitor charged to 200 V has 2000 (iC of charge. The value of capacitance will be

Solution (By Examveda Team)

Here's the explanation for the capacitance problem:

The question is about finding the capacitance of a capacitor.

First, remember the basic formula that connects charge (Q), voltage (V), and capacitance (C):
Q = C * V
where:
Q is the charge stored in the capacitor (in Coulombs).
C is the capacitance (in Farads).
V is the voltage across the capacitor (in Volts).

We are given:
Q = 2000 μC (which is 2000 * 10^-6 Coulombs)
V = 200 V

We need to find C.

Rearrange the formula to solve for C:
C = Q / V

Substitute the given values:
C = (2000 * 10^-6) / 200
C = 10 * 10^-6 F
C = 10 μF (microFarads)

So, the correct answer is Option B: 10 uF.