A certain series RLC circuit with a 200 Hz, 15 V ac source has the following values: R = 12 Ω, C = 80 µF, and L = 10 mH. The total impedance, expressed in polar form, is
A. 12.28 ∠12.34° Ω
B. 12.57 ∠12.34° Ω
C. 9.95 ∠12.34° Ω
D. 12.62 ∠12.34° Ω
Answer: Option A
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Related Questions on RLC Circuits and Resonance
A. Increase
B. Remain the same
C. Decrease
D. Be less selective
Z=sqrt(R^2 + (Xl-Xc)^2)
Xl=2*pi*f*L
Xc=1/(2*pi*f*C)
For angle θ,
θ = tangent inverse*(XL-XC/R)