ExamVeda
Login
Home

A circle inscribed in a triangle ABC touches its sides AB...

This question belongs to Arithmetic Ability Geometry
Geometry
?

A circle inscribed in a triangle ABC touches its sides AB, BC and AC at the points D, E and F, respectively. If AB = 18 cm, BC = 15 cm and AC = 13 cm, then the value of AD + BE + CF is:

Answer & Solution
Correct Answer: Option C
Geometry mcq question image
2(x + y + z) = 46
x + y + z = 23
AD + BE + CF = 23
Note:-
Geometry mcq question image
Perimeter of Δ = 2(x + y + z)
Then, AD + BE + CF = x + y + z
If a circle is inscribe into a triangle touches the side AB. BC & CA at D, E & F.
Then AD + BE + CF = $$\frac{1}{2}$$ × Perimeter of ΔABC
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.
Keep Learning

Related Questions on Geometry

ln a square ABCD, diagonals AC and BD interest at O. The angle bisector of ∠CAB meets BD and BC at F and G, respectively. OF : CG is equal to:
A. 1 : 2 B. 1 : 3 C. 1 : √3 D. 1 : √2
In the given figure, PQR is a triangle and quadrilateral ABCD is inscribed in it, QD = 2 cm, QC = 5 cm, CR = 3 cm, BR = 4 cm, PB = 6 cm, PA = 5 cm and AD = 3 cm. What is the area (in cm2) of the quadrilateral ABCD?
Geometry mcq question image
A. $$\frac{{23\sqrt {21} }}{4}$$ B. $$\frac{{15\sqrt {21} }}{4}$$ C. $$\frac{{17\sqrt {21} }}{5}$$ D. $$\frac{{23\sqrt {21} }}{5}$$
In ΔABC, AC = BC and ∠ABC = 50°, the side BC is produced to D so that BC = CD then the value of ∠BAD?
A. 80° B. 40° C. 90° D. 50°
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
Geometry mcq question image
A. 30° B. 40° C. 20° D. 70°
More Related Questions on Geometry