A circle is inscribed in a triangle ABC. It touches side AB, BC and AC at points R, P and Q, respectively. If AQ = 2.6 cm, PC = 2.7 cm and BR = 3 cm, then the perimeter (in cm) of the triangle ΔABC is:
A. 28
B. 30
C. 16.6
D. 33.2
Answer: Option C
Solution (By Examveda Team)
Because tangent drawn from a single point are equal.
So perimeter of ABC = (2.6 + 2.7 + 3) × 2 = 16.6
This Question Belongs to Arithmetic Ability >> Geometry
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