A circle touches the side BC of ΔABC at D and AB and AC are produced to E and F, respectively. If AB = 10 cm, AC = 8.6 cm and BC = 6.4 cm, then BE = ?
A. 2.2 cm
B. 3.2 cm
C. 3.5 cm
D. 2.5 cm
Answer: Option D
Solution (By Examveda Team)

10 + x = 8.6 + y (AE = AF)
x - y = -1.4 . . . . . . (i)
x + y = 6.4 . . . . . . (ii)
2x = 5.0
x = 2.5
BE = 2.5
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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