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A circular wire of length 168 cm is cut and bent in the form of rectangle whose sides are in the ratio of 5 : 7, what is the length (in cm) of the diagonal of rectangle?
Answer & Solution
Correct Answer:
Option
D
Perimeter of rectangle
2(5x + 7x) = 168
5x + 7x = 84
12x = 84
x = 7
Sides of rectangle = 35 cm, 49 cm
$$\eqalign{ & {\text{AC}} = \sqrt {{{35}^2} + {{49}^2}} \cr & {\text{AC}} = \sqrt {1225 + 2401} \cr & {\text{AC}} = \sqrt {3626} \cr} $$
2(5x + 7x) = 168
5x + 7x = 84
12x = 84
x = 7
Sides of rectangle = 35 cm, 49 cm
$$\eqalign{ & {\text{AC}} = \sqrt {{{35}^2} + {{49}^2}} \cr & {\text{AC}} = \sqrt {1225 + 2401} \cr & {\text{AC}} = \sqrt {3626} \cr} $$
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