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A closed system is cooled reversibly from 100°C to 50°C. If no work is done on the system
Answer & Solution
Correct Answer:
Option
B
Since here heat is taken from the system \[Q = - ve\]
From second law of thermodynamics \[TdS \ge \delta Q\]
Since given reversible process \[TdS = \delta Q\]
$$ \Rightarrow dS = - ve$$
From first law of thermodynamics
$$\eqalign{ & \delta Q = dU \cr & \Rightarrow dU = - ve \cr} $$
From second law of thermodynamics \[TdS \ge \delta Q\]
Since given reversible process \[TdS = \delta Q\]
$$ \Rightarrow dS = - ve$$
From first law of thermodynamics
$$\eqalign{ & \delta Q = dU \cr & \Rightarrow dU = - ve \cr} $$
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