?
A complete factorisation of x4 + 64 is?
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& \left( {{x^4} + 64} \right) \cr
& = {x^4} + {8^2} + 2.{x^2}.8 - 2.{x^2}.8 \cr
& = {\left( {{x^2} + 8} \right)^2} - \left( {16{x^2}} \right) \cr
& = {\left( {{x^2} + 8} \right)^2} - {\left( {4x} \right)^2} \cr
& = \left( {{x^2} + 8 + 4x} \right)\left( {{x^2} + 8 - 4x} \right) \cr
& = \left( {{x^2} + 4x + 8} \right)\left( {{x^2} - 4x + 8} \right) \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login