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A cubic cell consists of two atoms of masses m, and m2(m1 > m2) with m1 and m2 atoms situated on alternate planes. Assuming only nearest neighbour interactions, the centre of mass of the two atoms

A. moves with the atoms in the optical mode and remains fixed in the acoustic mode

B. remains fixed in the optical mode and moves with the atoms in the acoustic mode

C. remains fixed in both optical and acoustic modes

D. moves with the atoms in both optical and acoustic modes

Answer: Option B


This Question Belongs to Engineering Physics >> Solid State Physics

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In a cubic crystal, atoms of mass M1 lie on one set of planes and atoms of mass M2 lie on planes interleaved between those of the first set. If C is the forte constant between nearest neighbour planes, the frequency of lattice vibrations for the optical phonon branch with wave vector k = 0 is

A. $$\sqrt {2C\left( {\frac{1}{{{M_1}}} + \frac{1}{{{M_2}}}} \right)} $$

B. $$\sqrt {C\left( {\frac{1}{{2{M_1}}} + \frac{1}{{{M_2}}}} \right)} $$

C. $$\sqrt {C\left( {\frac{1}{{{M_1}}} + \frac{1}{{2{M_2}}}} \right)} $$

D. zero