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This question belongs to Arithmetic Ability Chain Rule
Chain Rule
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A garrison had provision for a certain number of days. After 10 days, $$\frac{1}{5}$$ of the men desert and it is found that the provisions will now last just as long as before. How long was that ?

Answer & Solution
Correct Answer: Option D
Initially, Let there be x men having food for y days
After 10 days, x men had food for days (y - 10)
Also, $$\left( {x - \frac{x}{5}} \right)$$   men had food for y days
$$\eqalign{ & \therefore \,x\left( {y - 10} \right) = \frac{{4x}}{5} \times y \cr & \Leftrightarrow 5xy - 50x = 4xy \cr & \Leftrightarrow xy - 50x = 0 \cr & \Leftrightarrow x\left( {y - 50} \right) = 0 \cr & \Leftrightarrow y - 50 = 0 \cr & \Leftrightarrow y = 50 \cr} $$
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1 Comment
Apo Chandra
Apo Chandra 5 years ago
Let men=m day=d
ATQ
md=10m+4m/5 ×d we know that TW=D×E
=>5md=50m+4md
=>md=50m
=>d=50