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A half-wave rectifier has an input voltage of 240 V r.m.s. If the step-down transformer has a turns ratio of 8:1, what is the peak load voltage? Ignore diode drop.

A. 27.5 V

B. 86.5 V

C. 30 V

D. 42.5 V

Answer: Option D


This Question Belongs to Electrical Engineering >> Semiconductor Diode

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Comments ( 6 )

  1. Lavito Achumi
    Lavito Achumi :
    1 year ago

    Secondary Voltage=240/8 = 30V
    Peak Load Voltage= √2 x 30 = 42.5V

  2. Om Jariwala
    Om Jariwala :
    3 years ago

    The

    .... filter circuit

    results in the best voltage regulation

    1. choke input

    2. capacitor input

    3. resistance input

    4. none of the above

  3. Harihara Parida
    Harihara Parida :
    4 years ago

    Emf/ turn are constant in a transferred.
    Secondary vtg = 240/8= 30
    In half wave rectifier pic= ✓2 x Vm
    ✓2*30=42.5.

  4. Engr Farman
    Engr Farman :
    4 years ago

    V1/V2 =N1/N2
    Vrms = 0.707Vo

  5. Engr Farman
    Engr Farman :
    4 years ago

    Vrms= 0.707 Vo
    Vo=240/8 = 30

  6. Jayanth Sparrow
    Jayanth Sparrow :
    6 years ago

    I want clarify in this

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