A man born in the first half of the nineteenth century was x years old in the year x². He was born in ?

A. 1806

B. 1812

C. 1825

D. 1836

Answer: Option A

Solution(By Examveda Team)

Clearly, the man was born between 1800 and 1850 is 1849.
$${\text{And, }}1849 = {\left( {43} \right)^2}$$
So, the man was 43 years old in 1849
$$\eqalign{ & {\text{Thus, he was born in }} \cr & = \left( {1849 - 43} \right) \cr & = 1806 \cr} $$