A manufacturer claims to have a heat engine capable of developing 20 h.p. by receiving heat input of 400 kcal/mt and working between the temperature limits of 227°C and 27°C. His claim is

hanna ck plz write the correct explanation

What vinodini murugan written completely wrong

Output = 20 h.p = 14.914 Kw ( 1hp = 0.746 kW)

input = 400 Kcal/min = 27.8932 (1k cal/min = 0.07 kW)

Higher temperature ( T ) = 227° C = 273 + 227 = 500°C

Lower temperature ( t ) = 27° C =  273 + 27 = 300°C

Ideal coeffiecient of performance =   = 0.4

Actual cop = output /input = 14.914/27.8932   = 0.532

Here the actual cop is greater than ideal which is not possible.

Therefore his claim is false

Read more on Brainly.in - https://brainly.in/question/15157830#readmore

1hp = 746 watt
1 metric tonn= 1000kg
Ans B not possible

How