A medium is divided into regions I and II about x = 0 plane, as shown in the figure below. An electromagnetic wave with electric field $${\overrightarrow E _1} = 4{{\hat a}_x} + 3{{\hat a}_y} + 5{{\hat a}_z}$$     is incident normally on the interface from region-I. The electric field $${\overrightarrow E _2}$$ in region-II at the interface is

A. $${\overrightarrow E _2} = {\overrightarrow E _1}$$

B. $$4{{\hat a}_x} + 0.75{{\hat a}_y} - 1.25{{\hat a}_z}$$

C. $$3{{\hat a}_x} + 3{{\hat a}_y} + 5{{\hat a}_z}$$

D. $$ - 3{{\hat a}_x} + 3{{\hat a}_y} + 5{{\hat a}_z}$$

Answer: Option C