A monkey climbs a 60 m high pole. In first minute he climbs 6 m and slips down 3 m in the next minute. How much time is required by it to reach the top?
A. 35 minutes
B. 33 minutes
C. 37 minutes
D. 40 minutes
Answer: Option C
Solution(By Examveda Team)
Monkey climbs 6 m in 1st minute and slips down 3 m in next minute i.e. Monkey climbs 3 meter in 2 minute then he climbs in one minute, = $$\frac{3}{2}$$ m. But in the last minute he climbs 6 m as he gets on the top so there is no slip. Time required = $$2 \times \frac{{54}}{3} + \frac{6}{6}$$ = 37 minutes.Related Questions on Speed Time and Distance
A. 48 min.
B. 60 min.
C. 42 min.
D. 62 min.
E. 66 min.
A. 262.4 km
B. 260 km
C. 283.33 km
D. 275 km
E. None of these
A. 4 hours
B. 4 hours 30 min.
C. 4 hours 45 min.
D. 5 hours
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