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A one-dimensional harmonic oscillator carrying a charge -q is placed in a uniform electric field $$\overrightarrow {\bf{E}} $$ along the positive X-axis. The corresponding Hamiltonian operator is

A. $$\frac{{{\hbar ^2}}}{{2m}}\frac{{{d^2}}}{{d{x^2}}} + \frac{1}{2}k{x^2} + qEx$$

B. $$\frac{{{\hbar ^2}}}{{2m}}\frac{{{d^2}}}{{d{x^2}}} + \frac{1}{2}k{x^2} - qEx$$

C. $$ - \frac{{{\hbar ^2}}}{{2m}}\frac{{{d^2}}}{{d{x^2}}} + \frac{1}{2}k{x^2} + qEx$$

D. $$ - \frac{{{\hbar ^2}}}{{2m}}\frac{{{d^2}}}{{d{x^2}}} + \frac{1}{2}k{x^2} - qEx$$

Answer: Option D


This Question Belongs to Engineering Physics >> Quantum Mechanics

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