A one-dimensional harmonic oscillator is in the state $$\psi \left( x \right) = \frac{1}{{\sqrt {14} }}\left[ {3{\psi _0}\left( x \right) - 2{\psi _1}\left( x \right) + {\psi _2}\left( x \right)} \right],$$ where, $${\psi _0}\left( x \right),\,{\psi _1}\left( x \right)$$ and $${\psi _2}\left( x \right)$$ are the ground, first excited and second excited states, respectively. The probability of finding the oscillator in the ground state is
A. zero
B. $$\frac{3}{{\sqrt {14} }}$$
C. $$\frac{9}{{14}}$$
D. 1
Answer: Option C
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