A particle is moving in a spherically symmetric potential V(r) = αr2, where α is a positive constant. In a stationary state, the expectation value of the kinetic energy $$\left\langle T \right\rangle $$ of the particle is
A. $$\left\langle T \right\rangle = \left\langle V \right\rangle $$
B. $$\left\langle T \right\rangle = 2\left\langle V \right\rangle $$
C. $$\left\langle T \right\rangle = 3\left\langle V \right\rangle $$
D. $$\left\langle T \right\rangle = 4\left\langle V \right\rangle $$
Answer: Option B
A. In the ground state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half
B. In the first excited state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half This also holds for states with n = 4, 6, 8, . . . .
C. For an arbitrary state $$\left| \psi \right\rangle ,$$ the probability of finding the particle in the left half of the well is half
D. In the ground state, the particle has a definite momentum
A. (e-ax1 - e-ax2)
B. a(e-ax1 - e-ax2)
C. e-ax2 (e-ax1 - e-ax2)
D. None of the above
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