A particle of mass m is represented by the wave function $$\psi \left( x \right) = A{e^{ikx}},$$ where k is the wave vector and A is a constant. The magnitude of the probability current density of the particle is
A. $${\left| A \right|^2}\frac{{\hbar k}}{m}$$
B. $${\left| A \right|^2}\frac{{\hbar k}}{{2m}}$$
C. $${\left| A \right|^2}\frac{{{{\left( {\hbar k} \right)}^2}}}{m}$$
D. $${\left| A \right|^2}\frac{{{{\left( {\hbar k} \right)}^2}}}{{2m}}$$
Answer: Option A
A. In the ground state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half
B. In the first excited state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half This also holds for states with n = 4, 6, 8, . . . .
C. For an arbitrary state $$\left| \psi \right\rangle ,$$ the probability of finding the particle in the left half of the well is half
D. In the ground state, the particle has a definite momentum
A. (e-ax1 - e-ax2)
B. a(e-ax1 - e-ax2)
C. e-ax2 (e-ax1 - e-ax2)
D. None of the above

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