ExamVeda
Login
Home
Mathematical Physics
?

A periodic function f(x) = x for -π < x < +π has the Fourier series representation \[f\left( x \right) = \sum\limits_{n = 1}^\infty {\left( { - \frac{2}{n}} \right){{\left( { - 1} \right)}^n}\sin nx.} \]
Using this, one finds the sum \[\sum\limits_{n = 1}^\infty {{n^{ - 2}}} \]   to be

Answer & Solution
Correct Answer: Option C
Let's discuss the solution. Join the discussion
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.