A periodic function f(x) = x for -π < x < +π has the Fourier series representation \[f\left( x \right) = \sum\limits_{n = 1}^\infty {\left( { - \frac{2}{n}} \right){{\left( { - 1} \right)}^n}\sin nx.} \]
Using this, one finds the sum \[\sum\limits_{n = 1}^\infty {{n^{ - 2}}} \] to be
A. 2$$l$$n 2
B. \[\frac{{{\pi ^2}}}{3}\]
C. \[\frac{{{\pi ^2}}}{6}\]
D. π$$l$$n 2
Answer: Option C


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