A product is an assemble of 5 different components. The product can be sequentially assembled in two different ways. If 5 components are placed in a box and these are drawn at random from the box, then probability of getting a correct sequence is
A. $$\frac{2}{{5!}}$$
B. $$\frac{2}{5}$$
C. $$\frac{2}{{\left( {5 - 2} \right)!}}$$
D. $$\frac{2}{{\left( {5 - 3} \right)!}}$$
Answer: Option A
This Question Belongs to Engineering Maths >> Probability And Statistics
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A. E(XY) = E(X) E(Y)
B. Cov (X, Y) = 0
C. Var (X + Y) = Var (X) + Var (Y)
D. E(X2Y2) = (E(X))2 (E(Y))2
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