A resistor of 10 kΩ with 5% tolerance is connected in parallel with a 5 kΩ resistor of 10% tolerance. What is the tolerance limit for the parallel network?

A) 5% B) 6.67% C) 10% D) 8.33%

Answer & Solution

Correct Answer: Option D

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Question posted by Examveda

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4 Comments

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VANAM MANI 4 years ago

Thank you Sajjad Ahamad

Sajjad Ahamad 5 years ago

Tolerance:-
∆R1 = 10*5/100 = .5kΩ
∆R2 = 5*10/100 = .5kΩ
∆Req = .5*.5/.5+.5 = 2.5kΩ [since connected in parallel]
Equivalent Resistance:-
R1 = 10kΩ, R2 = 5kΩ
Req = 10*5/5+10 = 10/3 = 3.33kΩ
Tolerance limit of parallel network:-
3.33*2.5kΩ
8.33%

Brij N. 5 years ago

tolerance=Req(5/10k +10/5k)
=3.33k*2.5
=8.33

Kiran Marathi 7 years ago

Please share detailed description

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A resistor of 10 k with 5 tolerance is connected in...

A resistor of 10 kΩ with 5% tolerance is connected in parallel with a 5 kΩ resistor of 10% tolerance. What is the tolerance limit for the parallel network?

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