A resistor of 10 kΩ with 5% tolerance is connected in parallel with a 5 kΩ resistor of 10% tolerance. What is the tolerance limit for the parallel network?
A. 5%
B. 6.67%
C. 10%
D. 8.33%
Answer: Option D
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Thank you Sajjad Ahamad
Tolerance:-
∆R1 = 10*5/100 = .5kΩ
∆R2 = 5*10/100 = .5kΩ
∆Req = .5*.5/.5+.5 = 2.5kΩ [since connected in parallel]
Equivalent Resistance:-
R1 = 10kΩ, R2 = 5kΩ
Req = 10*5/5+10 = 10/3 = 3.33kΩ
Tolerance limit of parallel network:-
3.33*2.5kΩ
8.33%
tolerance=Req(5/10k +10/5k)
=3.33k*2.5
=8.33
Please share detailed description