A resonant circuit has a lower critical frequency of 7 kHz and an upper critical frequency of 13 kHz. The bandwidth of the circuit is

A. 6 kHz

B. 13 kHz

C. 20 kHz

D. 4 kHz

Answer: Option A

Solution(By Examveda Team)

The bandwidth (BW) of a resonant circuit can be calculated using the formula:

$$BW = \text{Upper Critical Frequency} - \text{Lower Critical Frequency}$$

In this case:

Lower Critical Frequency ($$f_1$$) = 7 kHz
Upper Critical Frequency ($$f_2$$) = 13 kHz

Now, we can calculate the bandwidth:

$$BW = f_2 - f_1 = 13 \, \text{kHz} - 7 \, \text{kHz} = 6 \, \text{kHz}$$

So, the bandwidth of the circuit is 6 kHz.

The correct answer is Option A: 6 kHz.