A secant is drawn from a point P to a circle so that it meets the circle first at A, then goes through the centre, and leaves the circle at B. If the length of the tangent from P to the circle is 12 cm, and the radius of the circle is 5 cm, then the distance from P to A is:
A. 8 cm
B. 12 cm
C. 18 cm
D. 10 cm
Answer: Option A
Solution (By Examveda Team)

PQ = 12 cm
r = 5 cm
PQ2 = PA × PB
122 = x(x + 10)
144 = x(x + 10)
x2 + 10x - 144 = 0
x2 + (18x - 8x) -144 = 0
x(x + 18) - 8(x + 18) = 0
x = 8, x = -18
PA = 8 cm
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


Join The Discussion