A selection committee is to be chosen consisting of 5 ex-technicians. Now there are 12 representatives from four zones. It has further been decided that if Mr. X is selected, Y and Z will not be selected and vice-versa. In how many ways it can be done?
A. 572
B. 672
C. 472
D. 372
Answer: Option B
Solution(By Examveda Team)
10C5 : when both are not included. 10C4 : when one of them is included. Number of ways= 10C5 + 10C4 + 10C4
= 672
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Comments ( 2 )
Related Questions on Permutation and Combination
A. 3! 4! 8! 4!
B. 3! 8!
C. 4! 4!
D. 8! 4! 4!
A. 7560,60,1680
B. 7890,120,650
C. 7650,200,4444
D. None of these
A. 8 × 9!
B. 8 × 8!
C. 7 × 9!
D. 9 × 8!
Wrong ans. The ans should be
9C5 + ( 9C4 × 3) = 504.
Or, cut the (and Z) portion to meet the given answer.
I didn't understand the solution. Can anyone briefly solve the problem.