A series R-L circuit {R = 4 Ω and L = 0.01 H} is excited by a voltage (in volt) v(t) = 283sin(300t + 90°). The current in the circuit will be

A. $$40\sin \left\{ {300t + {{53.1}^ \circ }} \right\}{\text{A}}$$

B. $$40\sin {53.1^ \circ }{\text{A}}$$

C. $$40\sqrt 2 \sin \left\{ {300t + {{53.1}^ \circ }} \right\}{\text{A}}$$

D. $$40\sqrt 2 \sin {53.1^ \circ }{\text{A}}$$

Answer: Option C