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A single stage impulse turbine with a diameter of 1.2 m runs at 3000 r.p.m. If the blade speed ratio is 0.42, then the inlet velocity of steam will be

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Correct Answer: Option C
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तेजेन्द्र भारद्वाज
तेजेन्द्र भारद्वाज 5 years ago
U=(pi*D*N)/60, u/v= 0.42
U=(3.14*1.2*3000)/60 = 188.40
V= 188.40/0.42= 442m/s =450m/s
রাকেশ সাউ
রাকেশ সাউ 7 years ago
Vb=πDN/60
= (π *1.2*3000)/60
=189 m/s
Inlet velocity of steam = blade velocity /blade
speed ratio
=189/.42
=450 m/ s