A single stage impulse turbine with a diameter of 1.2 m runs at 3000 r.p.m. If the blade speed ratio is 0.42, then the inlet velocity of steam will be
A. 79 m/s
B. 188 m/s
C. 450 m/s
D. 900 m/s
Answer: Option C
This Question Belongs to Mechanical Engineering >> Steam Boilers, Engines, Nozzles And Turbines
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U=(pi*D*N)/60, u/v= 0.42
U=(3.14*1.2*3000)/60 = 188.40
V= 188.40/0.42= 442m/s =450m/s
Vb=πDN/60
= (π *1.2*3000)/60
=189 m/s
Inlet velocity of steam = blade velocity /blade
speed ratio
=189/.42
=450 m/ s