A string of length 24 cm is bent first into a...

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A string of length 24 cm is bent first into a square and then into a right-angled triangle by keeping one side of the square fixed as its base. Then the area of triangle equals to:

A. 24 cm²

B. 60 cm²

C. 40 cm²

D. 28 cm²

Answer: Option A

Solution (By Examveda Team)

$$\eqalign{ & {\text{Side of square}} = \frac{{24}}{4} = 6 \cr & {\text{Then area of }}\Delta ABC = \frac{1}{2} \times 8 \times 6 = 24{\text{ c}}{{\text{m}}^2} \cr} $$

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