A student is required to answer 6 out of 10 questions divided into two groups each containing 5 questions. He is not permitted to attempt more than 4 from each group. In how many ways can he make the choice?
A. 210
B. 150
C. 100
D. 200
Answer: Option D
Solution(By Examveda Team)
Number of ways of choosing 6 from 10 = 10C6 = 210 Number of ways of attempting more than 4 from a group, = 2 × 5C5 × 5C1= 10 Required number of ways
= 210 - 10
= 200
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Comments ( 2 )
Related Questions on Permutation and Combination
A. 3! 4! 8! 4!
B. 3! 8!
C. 4! 4!
D. 8! 4! 4!
A. 7560,60,1680
B. 7890,120,650
C. 7650,200,4444
D. None of these
A. 8 × 9!
B. 8 × 8!
C. 7 × 9!
D. 9 × 8!
Find the probability that a letter chosen at random from the alphabet "Education " is either a vowel or one of the later
Here the student has to choose 6 questions from 10
Here there are 2 sections contains 5 from each section.
Student are not allowed to attend more than 4 questions from each sections
Here are the following possible way of taking questions from each sections
5C4 * 5C2 = 50
5C3 * 5C3 = 100
5C2 * 5C4 = 50
Summing up we get 200 as the possible choice we can make