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# A student is required to answer 6 out of 10 questions divided into two groups each containing 5 questions. He is not permitted to attempt more than 4 from each group. In how many ways can he make the choice?

A. 210

B. 150

C. 100

D. 200

### Solution(By Examveda Team)

Number of ways of choosing 6 from 10 = 10C6 = 210
Number of ways of attempting more than 4 from a group,
= 2 × 5C5 × 5C1
= 10
Required number of ways
= 210 - 10
= 200

This Question Belongs to Arithmetic Ability >> Permutation And Combination

1. Find the probability that a letter chosen at random from the alphabet "Education " is either a vowel or one of the later

2. Here the student has to choose 6 questions from 10
Here there are 2 sections contains 5 from each section.
Student are not allowed to attend more than 4 questions from each sections
Here are the following possible way of taking questions from each sections
5C4 * 5C2 = 50
5C3 * 5C3 = 100
5C2 * 5C4 = 50
Summing up we get 200 as the possible choice we can make

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