A student is required to answer 6 out of 10 questions divided into two groups each containing 5 questions. He is not permitted to attempt more than 4 from each group. In how many ways can he make the choice?
A. 210
B. 150
C. 100
D. 200
Answer: Option D
Solution(By Examveda Team)
Number of ways of choosing 6 from 10 = 10C6 = 210 Number of ways of attempting more than 4 from a group, = 2 × 5C5 × 5C1= 10 Required number of ways
= 210 - 10
= 200
This Question Belongs to Arithmetic Ability >> Permutation And Combination
Find the probability that a letter chosen at random from the alphabet "Education " is either a vowel or one of the later
Here the student has to choose 6 questions from 10
Here there are 2 sections contains 5 from each section.
Student are not allowed to attend more than 4 questions from each sections
Here are the following possible way of taking questions from each sections
5C4 * 5C2 = 50
5C3 * 5C3 = 100
5C2 * 5C4 = 50
Summing up we get 200 as the possible choice we can make