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A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel?

A. 392

B. 126

C. 26

D. 9

Answer: Option B

Solution(By Examveda Team)

There are 8 students and the maximum capacity of the cars together is 9.
We may divide the 8 students as follows:

Case I:
5 students in the first car and 3 in the second.
Hence, 8 students are divided into groups of 5 and 3 in 8C3 = 56 ways.

Case II:
4 students in the first car and 4 in the second.
So, 8 students are divided into two groups of 4 and 4 in 8C4 = 78 ways.
Therefore, the total number of ways in which 8 students can travel is:
56 + 70 = 126

This Question Belongs to Arithmetic Ability >> Permutation And Combination

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Comments ( 1 )

  1. Tanvir Alam
    Tanvir Alam :
    4 years ago

    8C5 + 8C4 = 58+70 = 126

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