A train A is moving northward with velocity 90km/hr . The driver of train observes that train B is moving with 72km/hr towards west .The velocity of train B with respect to signal man standing near to rail track?

Solution (By Examveda Team)

ANSWER: 115.25 km/hr at an angle of 38.66^o west of north

SOLUTION: (Using vector method)



v*cosX = 90 ------(1)
v*sinX = 72 ------(2)

Using (1) and (2) we get,
v = 115.25 km/hr
x= tan^-1(0.8) = 38.66^o

So with respect to signal man standing near to rail track train B is moving with speed 115.25 km/hr at an angle of 38.66^o west of north.