A train approaches a tunnel AB. Inside the tunnel is a cat located at a point that is 3/8 of the distance AB measured from the entrance A. When the train whistles the cat runs. If the cat moves to the entrance of the tunnel A, the train catches the cat exactly at the entrance. If the cat moves to the exit B, the train catches the cat exactly at the exist. The speed of the train is greater than the speed of the cat by what order?
A. 3 : 1
B. 4 : 1
C. 5 : 1
D. None of these
Solution(By Examveda Team)
Let the train be at a distance y from A. Let the length of the tunnel AB be 8x. Therefore, the cat is at 3x from A.
Now both the conditions given in the questions assume same time scenario. Therefore, the ratio of the speeds of
the cat and the train will be equal to the ratio of the distances traveled by them.
Required ratio,
= > y/3x = (y +8x)/5x
=> y = 12.
Therefore, ratio of the speed = y/3x = 12x/3x = 4 : 1.
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Here, Time is constant so distances covered by train AND cat will be in the ratio of their respective speeds.
Hence,
Let speed of train be 'u'
And speed of cat be 'v'
u/v= 5k+3k/5k-3k= 8k/2I = 4:1
want explanation