A train covers a distance of 3584 km in 2 days 8 hours. if it cover 1440 km on 1st day and 1608 km on the 2nd day. by how much does the average speed of the train for the remaining part of the journey differ from that for the entire journey?
A. 3 kmph more
B. 3 kmph less
C. 4 kmph less
D. 5 kmph less
Answer: Option A
Solution (By Examveda Team)
Average speed = Tatal DIstance traveled/Total time takenTotal time = 2 days + 8 hours = 56 hours
Average speed = 3584/56 = 64 km/hr
remaining part of journy = 3484 - (1440 + 1068) = 536 km
remaining time = 8 hours
Average speed of remaining part of journey = 536/8 = 67 km/hr
there fore 67 - 64 = 3 km/hr
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