A train leaves a station A at 7 am and reaches another station B at 11 am. Another train leaves B at 8 am and reaches A at 11.30 am. The two trains cross one another at
A. 8:36 am
B. 8:56 am
C. 9:00 am
D. 9:24 am
Answer: Option D
Solution (By Examveda Team)
Here's a breakdown of how to solve this train problem, explained in a simple way:First, let's figure out how long each train takes to complete its journey:
Train 1 (from A to B): It travels from 7:00 am to 11:00 am, which is a total of 4 hours.
Train 2 (from B to A): It travels from 8:00 am to 11:30 am, which is a total of 3.5 hours (or 3 and a half hours).
Now, imagine the distance between A and B as 'D'. We can calculate the speed of each train:
Speed of Train 1: D / 4 (Distance divided by time)
Speed of Train 2: D / 3.5 (Distance divided by time)
Let's see what happens in the first hour after Train 1 starts (from 7 am to 8 am). In this hour, only Train 1 is moving.
Now, consider the time after 8 am. Let 't' be the time (in hours) after 8 am when the trains meet.
In time 't', Train 1 covers a distance of (D/4) * t
In time 't', Train 2 covers a distance of (D/3.5) * t
When they meet, the combined distance covered by both trains will be equal to the distance between A and B (which is D). The important thing to note is that Train 1 has already been traveling for an hour (from 7am to 8am) before Train 2 departs.
Therefore the equation should be: (Distance covered by train 1 in 1 hour) + (Distance covered by train 1 in 't' hours) + (Distance covered by train 2 in 't' hours) = Total Distance
(D/4 * 1) + (D/4 * t) + (D/3.5 * t) = D
Now, simplify the equation by dividing the entire equation by D
(1/4) + (t/4) + (t/3.5) = 1
Solve for 't':
(t/4) + (t/3.5) = 1 - (1/4)
(t/4) + (t/3.5) = 3/4
To solve easily, convert 3.5 to 7/2
(t/4) + (2t/7) = 3/4
Find a common denominator to combine the t terms
(7t/28) + (8t/28) = 3/4
(15t/28) = 3/4
Multiply both sides by 28
15t = (3/4) * 28
15t = 21
t = 21/15 = 7/5 hours
Convert 7/5 hours into hours and minutes:
t = 1 hour and (2/5) of an hour
(2/5) of an hour = (2/5) * 60 minutes = 24 minutes
So, t = 1 hour and 24 minutes.
Since 't' is the time after 8:00 am, add 1 hour and 24 minutes to 8:00 am:
8:00 am + 1 hour 24 minutes = 9:24 am
Therefore, the two trains cross one another at 9:24 am.
The answer is (D).
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Vishal, what is b/w? Can you please explain?
Akhil R what is b/w? Can you please explain?
Time Ratio= 8:7 (4*2,3.5*2)
Speed Ratio= 7:8
Total Distance = 8*7= 56
Related speed of first train= 56/4 =14
Related speed of another train= 56/3.5 =16
Meeting Time =* 42/30 =7/5= 1 hrs 24 min.
so after 1 hrs 24 min. of 8am = 9.24am.//
42= 56-14 (Related speed of first train= 56/4 =14)
A. B
T 4. 7/2
28
S 7. 8
Total s=15
Covered by a in 1 hour=7
Remain distance=28-7=21
Meeting time= 21/15=7/5
7/5×60=84 min =1h24min
8+1h24m=9:24min
let distance b/w A & B is D
Vab = D/4 ..... Vba = 2D/7
let they meet at T hr after 8 am
D= D/4*(T+1) +2D/7*T
T= 7/5 = 1 hr 24 min
required time = 8 am + 1 hr 24 min
= 9:24 am
7-11 = 4hrs
8-11.30=3.5 hrs
A B
TIME 4 3.5
SPEED 35 40..........INVERSELY PROPORTIONATE
7 8 = 15
FIRST TRAIN ALREADY COVERED 1/2 DISTANCE......REMAIN = 1/2 D
1/2/ 7/15 = 7*2/15= 14/15 HRS.
14*60/15 = 56 MINS
MEETING TIME = 8+56 = 8 HRS 56 MINS
D) 9:24 am
8.56am
d
9:24