A train which travels at a uniform speed due to some mechanical fault after traveling for an hour goes at 3/4th of the original speed and reached the destination 2 hours late. If the fault has occurred after traveling another 50 miles, the train would have reached 40 minutes earlier. what is the distance between the two stations?

Solution (By Examveda Team)

Let, the original speed is x and 3/5 th of original speed is 0.6x

50/0.6x - 50/x= 40/60
(250-150)/3x = 2/3
100/3x = 2/3
6x=300
x=50

3/5 of 50 = 30
speed reduces by = 50-30 = 20
It is late by 2 hours and by this time it goes 30*2 = 60
If the train goes with its original speed it took 60/20 = 3 hours after the first hour. That means total 4 hours.
Therefore, total distance covered 4*50 = 200 and speed is 50.