A two member committee comprising of one male and one female member is to be constitute out of five males and three females. Amongst the females. Ms. A refuses to be a member of the committee in which Mr. B is taken as the member. In how many different ways can the committee be constituted ?

(2×5)+(3×4)
=22

(5C1*3C1)-1
=(5!/4!*3!/2!)-1
=(5*3)-1
=15-1
=14
Answer :- 14

It may b clear tht one men and one women
Selected as 5c1*3c1
15

Now A female and B male can be selected frm this only once no..
Ie only one time a and b come together.

So if u minus 15-1..14 times they don't come tgthr

we have to select 1 male members from 5 males and 1 female member
from 3 females if B male taken as a member then A refuses to a member
hence BA can not be a members
5c1*3c1-1

please explain me the solution of this problem in details. I m not getting it. Reply asap. thank u.

Please give full explanation.