# A two member committee comprising of one male and one female member is to be constitute out of five males and three females. Amongst the females. Ms. A refuses to be a member of the committee in which Mr. B is taken as the member. In how many different ways can the committee be constituted ?

A. 11

B. 12

C. 13

D. 14

**Answer: Option D **

__Solution(By Examveda Team)__

^{5}C

_{1}×

^{3}C

_{1}- 1

= 15 - 1

= 14

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## Comments ( 6 )

Related Questions on Permutation and Combination

A. 3! 4! 8! 4!

B. 3! 8!

C. 4! 4!

D. 8! 4! 4!

A. 7560,60,1680

B. 7890,120,650

C. 7650,200,4444

D. None of these

A. 8 × 9!

B. 8 × 8!

C. 7 × 9!

D. 9 × 8!

(2×5)+(3×4)

=22

(5C1*3C1)-1

=(5!/4!*3!/2!)-1

=(5*3)-1

=15-1

=14

Answer :- 14

It may b clear tht one men and one women

Selected as 5c1*3c1

15

Now A female and B male can be selected frm this only once no..

Ie only one time a and b come together.

So if u minus 15-1..14 times they don't come tgthr

we have to select 1 male members from 5 males and 1 female member

from 3 females if B male taken as a member then A refuses to a member

hence BA can not be a members

5c1*3c1-1

please explain me the solution of this problem in details. I m not getting it. Reply asap. thank u.

Please give full explanation.