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A weight of 1000 N can be lifted by an effort of 80 N. If the velocity ratio is 20, the machine is

A. Reversible

B. Non-reversible

C. Ideal

D. None of these

Answer: Option A


This Question Belongs to Mechanical Engineering >> Engineering Mechanics

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Comments ( 6 )

  1. Balaraj Honnamude
    Balaraj Honnamude :
    3 months ago

    Efficiency=MA/VR
    MA(Mechanical Advantage)=W/P
    W=1000, P=80, VR=20
    If Efficiency is equal to MA and VA then Machine is ideal
    Efficiency is greater than 50% then Machine is Reversible
    Efficiency is less than 50% then Machine is non reversible or self locking machine

  2. CHUDAM LE
    CHUDAM LE :
    2 years ago

    W= 1000N P=80N V.R= 20
    WE KNOW, EFFICENCY= M.A / V.R

    M.A= W/P = 1000/80= 12.5


    EFFICENCY= 12.5/20= 0.625 = 62.5%

  3. Arif Malek
    Arif Malek :
    3 years ago

    M.a- load lift to efforts applied 1000/80=12.5
    12.5/20×100= 62.5>50 reversible

  4. VINU KARDILE
    VINU KARDILE :
    3 years ago

    Reversible machine : A machine which is capable of doing work in the reverse direction even after the removal of effort ,load get lifted is called Reversible machine.
    Non - Reversible machine : A machine which is not capable of doing work in the reverse direction is called Non - Reversible machine. {It is also called self- locking machine} {For non-reversible machine efficiency will be less than 50%}
    The term ideal machine refers to a hypothetical mechanical system in which energy and power are not lost or dissipated through friction, deformation, wear, or other inefficiencies.

  5. Shripat Kambale
    Shripat Kambale :
    4 years ago

    Efficiency =Mechanical advantage /velocity ratio
    =12.5/20 *100= 62.5 >50 %

  6. Shubham Mishra
    Shubham Mishra :
    5 years ago

    how?

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