ABC is a right angled triangle, right angled at A. A circle is inscribed in it. The lengths of two sides containing the right angle are 48 cm and 14 cm. The radius of the inscribed circle is:
A. 4 cm
B. 6 cm
C. 8 cm
D. 5 cm
Answer: Option B
Solution (By Examveda Team)
BC2 = 482 + 142
BC2 = 2304 + 196
BC2 = 2500
BC = 50 cm
In radius r = $$\frac{{14 + 48 - 50}}{2}$$ = 6 cm
This Question Belongs to Arithmetic Ability >> Geometry
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B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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