ABC is a triangle in which ∠ABC = 90°. BD is perpendicular to AC. Which of the following is TRUE?
I. Triangle BAD is similar to triangle CBD.
II. Triangle BAD is similar to triangle CAB.
III. Triangle CBD, is similar to triangle CAB.
A. Only I
B. Only II and III
C. Only I and III
D. All I, II and III
Answer: Option D
Solution (By Examveda Team)

In ΔBAD and ΔBDC
∠BDA = ∠BDC (Each 90°)
If ∠C = 30°
Then ∠A = 60°
Also ∠ABD = 30°
∠BCD = ∠ABD
ΔBAD ∼ ΔBDC . . . . . (i)
In ΔBAD and ΔCAB
∠BDA = ∠ABC (Each 90°)
∠BAD = ∠BAC (common)
ΔBAD ∼ ΔCAB . . . . . (ii)
Similarly ΔCBD ∼ ΔCAB . . . . . (iii)
All conditions are true.
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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